用 Query Store 查找执行计划回归（同一查询，不同计划）

命令

USE [Musteri];
-- Queries with more than one plan in the last 24 hours, per-plan performance:
WITH plan_stats AS (
    SELECT p.query_id, p.plan_id, p.is_forced_plan,
           SUM(rs.count_executions) AS execs,
           SUM(rs.avg_duration * rs.count_executions) / SUM(rs.count_executions) / 1000.0     AS avg_ms,
           SUM(rs.avg_cpu_time * rs.count_executions) / SUM(rs.count_executions) / 1000.0     AS avg_cpu_ms,
           SUM(rs.avg_logical_io_reads * rs.count_executions) / SUM(rs.count_executions)      AS avg_reads,
           MAX(rs.last_execution_time) AS last_exec
    FROM   sys.query_store_plan p
      JOIN sys.query_store_runtime_stats rs ON rs.plan_id = p.plan_id
      JOIN sys.query_store_runtime_stats_interval i
        ON i.runtime_stats_interval_id = rs.runtime_stats_interval_id
    WHERE  i.start_time >= DATEADD(HOUR, -24, SYSUTCDATETIME())
    GROUP BY p.query_id, p.plan_id, p.is_forced_plan
)
SELECT ps.query_id, ps.plan_id, ps.is_forced_plan, ps.execs,
       CAST(ps.avg_ms AS DECIMAL(18,2))     AS avg_ms,
       CAST(ps.avg_cpu_ms AS DECIMAL(18,2)) AS avg_cpu_ms,
       CAST(ps.avg_reads AS BIGINT)         AS avg_reads,
       CAST(ps.avg_ms / NULLIF(MIN(ps.avg_ms) OVER (PARTITION BY ps.query_id), 0) AS DECIMAL(18,1)) AS x_slower_than_best,
       ps.last_exec,
       OBJECT_NAME(q.object_id)     AS module,
       LEFT(qt.query_sql_text, 120) AS query_text
FROM   plan_stats ps
  JOIN sys.query_store_query q       ON q.query_id = ps.query_id
  JOIN sys.query_store_query_text qt ON qt.query_text_id = q.query_text_id
WHERE  ps.query_id IN (SELECT query_id FROM plan_stats GROUP BY query_id HAVING COUNT(*) > 1)
ORDER BY ps.query_id, ps.avg_ms;

作用

找出过去 24 小时内以多个执行计划运行过的查询；并列显示每个计划的执行次数、加权平均持续时间/CPU/读取量，以及比最佳计划慢多少倍。

适用场景

查询“昨天还快、今天变慢”时，以及统计信息更新、索引变更、兼容级别升级或打补丁之后。

注意

平均持续时间也取决于数据分布；比较以不同参数值运行的计划时，也要看 avg_reads（参数嗅探）。时间窗口为 UTC。执行次数少的计划结果在统计上不可靠。只读查询；安全。